c#用相同的方法选择文件夹或文件

这是我发现的在不依赖第三方代码的情况下解决此问题的最简单方法，但您需要添加一些健全性检查，以防用户在输入时出错：

        OpenFileDialog ofd = new OpenFileDialog();
        ofd.CheckFileExists = false;
        string defaultFilename = "Select this folder";
        ofd.FileName = defaultFilename;
        if (ofd.ShowDialog().Value)
        {
            // Check if the user picked a file or a directory, for example:
            if (!ofd.FileName.Contains(defaultFilename))
            {
                // File code
            }
            else // You should probably turn this into an else if instead
            {
                // Directory code
            }
            // Alternatively, but still as unsafe
            if (File.Exists(ofd.FileName))
            {
                // File code
            }
            else
            {
                // Directory code
            }
        }

基本上，这里的"窍门"是将OpenFileDialog的CheckFileExists设置为false。

尝试使用FolderBrowserDialogEx。

请在此处查看详细答案：如何配置OpenFileDialog来选择文件夹？

两个对话框（FileOpenDialog和FolderBrowserDialog）都继承自CommonDialog；但是，这个基类没有用于检索结果的属性。此外，属性在两个对话框中的命名也不同。

你可以通过创建一个包装来解决这个问题。继承是将对象重新定义为不同类型的正确方法。

public abstract class FileFolderDialogBase
{
    public abstract bool ShowDialog();
    public string Result { get; protected set; }
}
public class FileDialog : FileFolderDialogBase
{
    public override bool ShowDialog()
    {
        var ofd = new OpenFileDialog();
        if ofd.ShowDialog() == DialogResult.OK) {
            Result = ofd.FileName;
            return true;
        }
        return false;
    }
}
public class FolderDialog : FileFolderDialogBase
{
    public override bool ShowDialog()
    {
        var fbd = new FolderBrowserDialog();
        if (fbd.ShowDialog() == DialogResult.OK)
            Result = fbd.SelectedPath;
            return true;
        }
        return false;
    }
}

用法：

var dialog = textBox.Tag == "Folder" ? new FolderDialog() : new FileDialog;
if (dialog.ShowDialog()) {
    textBox.Text = dialog.Result;
}

你可以通过创建一个工厂级来进一步推动它

public static class FileFolderDialog
{
    public static FileFolderDialogBase Create(string type)
    {
        swich (type.ToLowerInvariant()) {
            case "folder":
            case "dir":
            case "directory":
                return new FolderDialog();
            default:
                return new FileDialog();
        }
    } 
}

使用

var dialog = FileFolderDialog.Create(textBox.Tag);
if (dialog.ShowDialog()) {
    textBox.Text = dialog.Result;
}

为什么不尝试扩展TextBox类？它简单且可重复使用，您只需要将自定义控件拖放到WinForm

    class FileTextBox : System.Windows.Form.TextBox{
       //===>This enumeration is more readable insted of a string XD
       public enum DialogType{
         File,Folder
       }
     //===>This property we will handle what kind of Dialog to show
    public DialogType OpenDialogType{
      get;
      set;
    }
    //===>This is where Object Oriented Programming a& Design do his magic
    public System.Windows.Forms.DialogResult ShowDialog(string Title =""){
      //===>This function is where we define what kind of dialog  to show
      System.Windows.Forms.DialogResult Result =   System.Windows.Forms.DialogResult.None ;
      object Browser=null;
           switch(this.OpenDialogType){
                  case DialogType.File:
                  Browser = new OpenFileDialog();
                  ((Browser)OpenFileDialog).Title= Title;
                   if(this.Text.Trim() !="" && this.Text != null ){
                     ((Browser)OpenFileDialog).FileName = this.Tex;
                   }
                  Result = ((Browser)OpenFileDialog).ShowDialog();
                  break;
                  case DialogType.Folder:
                  Browser = new FolderBrowserDialog ();
                  ((Browser)FolderBrowserDialog).Description = Title;
                  if(this.Text.Trim() !="" && this.Text != null ){
                      ((Browser)FolderBrowserDialog).RootFolder = this.Text; 
                  } 
                  Result = ((Browser)FolderBrowserDialog).ShowDialog();
                  break;
           }
    return Result;//===>We return thi dialog result just if we want to do something else
    }
}
/*
Create a class and copy/paste this code, I think is going to work because
I didn't compiled then go to ToolBox window find this control and Drag & Drop
to your WinForm and in the property window find OpenDialogType property
and this is where you kind define the behavior of OpenDialog();
I'm currently working in a little project in Vs where I create a custom
UI Control downloaded from my git repository 

https://github.com/MrAlex6204/GYMSystem

*/